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Java-based LeetCode algorithm problem solutions, regularly updated
729\. My Calendar I
Medium
You are implementing a program to use as your calendar. We can add a new event if adding the event will not cause a **double booking**.
A **double booking** happens when two events have some non-empty intersection (i.e., some moment is common to both events.).
The event can be represented as a pair of integers `start` and `end` that represents a booking on the half-open interval `[start, end)`, the range of real numbers `x` such that `start <= x < end`.
Implement the `MyCalendar` class:
* `MyCalendar()` Initializes the calendar object.
* `boolean book(int start, int end)` Returns `true` if the event can be added to the calendar successfully without causing a **double booking**. Otherwise, return `false` and do not add the event to the calendar.
**Example 1:**
**Input**
["MyCalendar", "book", "book", "book"]
[[], [10, 20], [15, 25], [20, 30]]
**Output:** [null, true, false, true]
**Explanation:**
MyCalendar myCalendar = new MyCalendar();
myCalendar.book(10, 20); // return True
myCalendar.book(15, 25); // return False, It can not be booked because time 15 is already booked by another event.
myCalendar.book(20, 30); // return True, The event can be booked, as the first event takes every time less than 20, but not including 20.
**Constraints:**
* 0 <= start < end <= 109
* At most `1000` calls will be made to `book`.