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Java-based LeetCode algorithm problem solutions, regularly updated
package g0901_1000.s0924_minimize_malware_spread;
// #Hard #Array #Depth_First_Search #Breadth_First_Search #Matrix #Union_Find
// #2022_04_29_Time_10_ms_(47.21%)_Space_55.1_MB_(83.27%)
public class Solution {
private int[] size;
private int[] par;
public int minMalwareSpread(int[][] graph, int[] initial) {
size = new int[graph.length];
par = new int[graph.length];
for (int i = 0; i < graph.length; i++) {
size[i] = 1;
par[i] = i;
}
// create groups
for (int i = 0; i < graph.length; i++) {
for (int j = 0; j < graph[0].length; j++) {
if (graph[i][j] == 1) {
int p1 = find(i);
int p2 = find(j);
merge(p1, p2);
}
}
}
// no of infected in group
int[] infected = new int[graph.length];
for (int e : initial) {
int p = find(e);
infected[p]++;
}
int currSize = -1;
int ans = -1;
for (int e : initial) {
int p = find(e);
if (infected[p] == 1 && size[p] >= currSize) {
if (size[p] > currSize) {
ans = e;
} else {
ans = Math.min(ans, e);
}
currSize = size[p];
}
}
// all groups have more than 1 infected node then return min value from initial
if (ans == -1) {
ans = initial[0];
for (int j : initial) {
ans = Math.min(ans, j);
}
}
return ans;
}
private void merge(int p1, int p2) {
if (p1 != p2) {
if (size[p1] > size[p2]) {
par[p2] = p1;
size[p1] += size[p2];
} else {
par[p1] = p2;
size[p2] += size[p1];
}
}
}
private int find(int u) {
if (par[u] == u) {
return u;
}
par[u] = find(par[u]);
return par[u];
}
}