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g1001_1100.s1040_moving_stones_until_consecutive_ii.readme.md Maven / Gradle / Ivy

1040\. Moving Stones Until Consecutive II

Medium

There are some stones in different positions on the X-axis. You are given an integer array `stones`, the positions of the stones.

Call a stone an **endpoint stone** if it has the smallest or largest position. In one move, you pick up an **endpoint stone** and move it to an unoccupied position so that it is no longer an **endpoint stone**.

*   In particular, if the stones are at say, `stones = [1,2,5]`, you cannot move the endpoint stone at position `5`, since moving it to any position (such as `0`, or `3`) will still keep that stone as an endpoint stone.

The game ends when you cannot make any more moves (i.e., the stones are in three consecutive positions).

Return _an integer array_ `answer` _of length_ `2` _where_:

*   `answer[0]` _is the minimum number of moves you can play, and_
*   `answer[1]` _is the maximum number of moves you can play_.

**Example 1:**

**Input:** stones = [7,4,9]

**Output:** [1,2]

**Explanation:** We can move 4 -> 8 for one move to finish the game. Or, we can move 9 -> 5, 4 -> 6 for two moves to finish the game.

**Example 2:**

**Input:** stones = [6,5,4,3,10]

**Output:** [2,3]

**Explanation:** We can move 3 -> 8 then 10 -> 7 to finish the game. 

Or, we can move 3 -> 7, 4 -> 8, 5 -> 9 to finish the game. 

Notice we cannot move 10 -> 2 to finish the game, because that would be an illegal move.

**Constraints:**

*   3 <= stones.length <= 104
*   1 <= stones[i] <= 109
*   All the values of `stones` are **unique**.