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Java-based LeetCode algorithm problem solutions, regularly updated
2549\. Count Distinct Numbers on Board
Easy
You are given a positive integer `n`, that is initially placed on a board. Every day, for 109
days, you perform the following procedure:
* For each number `x` present on the board, find all numbers `1 <= i <= n` such that `x % i == 1`.
* Then, place those numbers on the board.
Return _the number of **distinct** integers present on the board after_ 109
_days have elapsed_.
**Note:**
* Once a number is placed on the board, it will remain on it until the end.
* `%` stands for the modulo operation. For example, `14 % 3` is `2`.
**Example 1:**
**Input:** n = 5
**Output:** 4
**Explanation:** Initially, 5 is present on the board.
The next day, 2 and 4 will be added since 5 % 2 == 1 and 5 % 4 == 1.
After that day, 3 will be added to the board because 4 % 3 == 1.
At the end of a billion days, the distinct numbers on the board will be 2, 3, 4, and 5.
**Example 2:**
**Input:** n = 3
**Output:** 2
**Explanation:** Since 3 % 2 == 1, 2 will be added to the board. After a billion days, the only two distinct numbers on the board are 2 and 3.
**Constraints:**
* `1 <= n <= 100`