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Java-based LeetCode algorithm problem solutions, regularly updated
3005\. Count Elements With Maximum Frequency
Easy
You are given an array `nums` consisting of **positive** integers.
Return _the **total frequencies** of elements in_ `nums` _such that those elements all have the **maximum** frequency_.
The **frequency** of an element is the number of occurrences of that element in the array.
**Example 1:**
**Input:** nums = [1,2,2,3,1,4]
**Output:** 4
**Explanation:** The elements 1 and 2 have a frequency of 2 which is the maximum frequency in the array. So the number of elements in the array with maximum frequency is 4.
**Example 2:**
**Input:** nums = [1,2,3,4,5]
**Output:** 5
**Explanation:** All elements of the array have a frequency of 1 which is the maximum. So the number of elements in the array with maximum frequency is 5.
**Constraints:**
* `1 <= nums.length <= 100`
* `1 <= nums[i] <= 100`