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Kotlin-based LeetCode algorithm problem solutions, regularly updated
495\. Teemo Attacking
Easy
Our hero Teemo is attacking an enemy Ashe with poison attacks! When Teemo attacks Ashe, Ashe gets poisoned for a exactly `duration` seconds. More formally, an attack at second `t` will mean Ashe is poisoned during the **inclusive** time interval `[t, t + duration - 1]`. If Teemo attacks again **before** the poison effect ends, the timer for it is **reset**, and the poison effect will end `duration` seconds after the new attack.
You are given a **non-decreasing** integer array `timeSeries`, where `timeSeries[i]` denotes that Teemo attacks Ashe at second `timeSeries[i]`, and an integer `duration`.
Return _the **total** number of seconds that Ashe is poisoned_.
**Example 1:**
**Input:** timeSeries = [1,4], duration = 2
**Output:** 4
**Explanation:** Teemo's attacks on Ashe go as follows:
- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2.
- At second 4, Teemo attacks, and Ashe is poisoned for seconds 4 and 5.
- Ashe is poisoned for seconds 1, 2, 4, and 5, which is 4 seconds in total.
**Example 2:**
**Input:** timeSeries = [1,2], duration = 2
**Output:** 3
**Explanation:** Teemo's attacks on Ashe go as follows:
- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2.
- At second 2 however, Teemo attacks again and resets the poison timer. Ashe is poisoned for seconds 2 and 3.
- Ashe is poisoned for seconds 1, 2, and 3, which is 3 seconds in total.
**Constraints:**
* 1 <= timeSeries.length <= 104
* 0 <= timeSeries[i], duration <= 107
* `timeSeries` is sorted in **non-decreasing** order.