• Home
• com.github.javadev
• leetcode-in-kotlin
• 1.20
• source code
• readme.md

×

Project download

Many resources are needed to download a project. Please understand that we have to compensate our server costs. Thank you in advance.
Project price only 1 $

You can buy this project and download/modify it how often you want.

g0501_0600.s0514_freedom_trail.readme.md Maven / Gradle / Ivy

514\. Freedom Trail

Hard

In the video game Fallout 4, the quest **"Road to Freedom"** requires players to reach a metal dial called the **"Freedom Trail Ring"** and use the dial to spell a specific keyword to open the door.

Given a string `ring` that represents the code engraved on the outer ring and another string `key` that represents the keyword that needs to be spelled, return _the minimum number of steps to spell all the characters in the keyword_.

Initially, the first character of the ring is aligned at the `"12:00"` direction. You should spell all the characters in `key` one by one by rotating `ring` clockwise or anticlockwise to make each character of the string key aligned at the `"12:00"` direction and then by pressing the center button.

At the stage of rotating the ring to spell the key character `key[i]`:

1.  You can rotate the ring clockwise or anticlockwise by one place, which counts as **one step**. The final purpose of the rotation is to align one of `ring`'s characters at the `"12:00"` direction, where this character must equal `key[i]`.
2.  If the character `key[i]` has been aligned at the `"12:00"` direction, press the center button to spell, which also counts as **one step**. After the pressing, you could begin to spell the next character in the key (next stage). Otherwise, you have finished all the spelling.

**Example 1:**

![](https://assets.leetcode.com/uploads/2018/10/22/ring.jpg)

**Input:** ring = "godding", key = "gd"

**Output:** 4

**Explanation:** For the first key character 'g', since it is already in place, we just need 1 step to spell this character. For the second key character 'd', we need to rotate the ring "godding" anticlockwise by two steps to make it become "ddinggo". Also, we need 1 more step for spelling. So the final output is 4.

**Example 2:**

**Input:** ring = "godding", key = "godding"

**Output:** 13

**Constraints:**

*   `1 <= ring.length, key.length <= 100`
*   `ring` and `key` consist of only lower case English letters.
*   It is guaranteed that `key` could always be spelled by rotating `ring`.