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Kotlin-based LeetCode algorithm problem solutions, regularly updated
541\. Reverse String II
Easy
Given a string `s` and an integer `k`, reverse the first `k` characters for every `2k` characters counting from the start of the string.
If there are fewer than `k` characters left, reverse all of them. If there are less than `2k` but greater than or equal to `k` characters, then reverse the first `k` characters and leave the other as original.
**Example 1:**
**Input:** s = "abcdefg", k = 2
**Output:** "bacdfeg"
**Example 2:**
**Input:** s = "abcd", k = 2
**Output:** "bacd"
**Constraints:**
* 1 <= s.length <= 104
* `s` consists of only lowercase English letters.
* 1 <= k <= 104