g0501_0600.s0598_range_addition_ii.readme.md Maven / Gradle / Ivy
Go to download
Show more of this group Show more artifacts with this name
Show all versions of leetcode-in-kotlin Show documentation
Show all versions of leetcode-in-kotlin Show documentation
Kotlin-based LeetCode algorithm problem solutions, regularly updated
598\. Range Addition II
Easy
You are given an `m x n` matrix `M` initialized with all `0`'s and an array of operations `ops`, where ops[i] = [ai, bi]
means `M[x][y]` should be incremented by one for all 0 <= x < ai
and 0 <= y < bi
.
Count and return _the number of maximum integers in the matrix after performing all the operations_.
**Example 1:**
![](https://assets.leetcode.com/uploads/2020/10/02/ex1.jpg)
**Input:** m = 3, n = 3, ops = [[2,2],[3,3]]
**Output:** 4
**Explanation:** The maximum integer in M is 2, and there are four of it in M. So return 4.
**Example 2:**
**Input:** m = 3, n = 3, ops = [[2,2],[3,3],[3,3],[3,3],[2,2],[3,3],[3,3],[3,3],[2,2],[3,3],[3,3],[3,3]]
**Output:** 4
**Example 3:**
**Input:** m = 3, n = 3, ops = []
**Output:** 9
**Constraints:**
* 1 <= m, n <= 4 * 104
* 0 <= ops.length <= 104
* `ops[i].length == 2`
* 1 <= ai <= m
* 1 <= bi <= n