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Kotlin-based LeetCode algorithm problem solutions, regularly updated
886\. Possible Bipartition
Medium
We want to split a group of `n` people (labeled from `1` to `n`) into two groups of **any size**. Each person may dislike some other people, and they should not go into the same group.
Given the integer `n` and the array `dislikes` where dislikes[i] = [ai, bi]
indicates that the person labeled ai
does not like the person labeled bi
, return `true` _if it is possible to split everyone into two groups in this way_.
**Example 1:**
**Input:** n = 4, dislikes = [[1,2],[1,3],[2,4]]
**Output:** true
**Explanation:** The first group has [1,4], and the second group has [2,3].
**Example 2:**
**Input:** n = 3, dislikes = [[1,2],[1,3],[2,3]]
**Output:** false
**Explanation:** We need at least 3 groups to divide them. We cannot put them in two groups.
**Constraints:**
* `1 <= n <= 2000`
* 0 <= dislikes.length <= 104
* `dislikes[i].length == 2`
* 1 <= ai < bi <= n
* All the pairs of `dislikes` are **unique**.
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