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Kotlin-based LeetCode algorithm problem solutions, regularly updated
972\. Equal Rational Numbers
Hard
Given two strings `s` and `t`, each of which represents a non-negative rational number, return `true` if and only if they represent the same number. The strings may use parentheses to denote the repeating part of the rational number.
A **rational number** can be represented using up to three parts: ``, ``, and a ``. The number will be represented in one of the following three ways:
* ``
* For example, `12`, `0`, and `123`.
* **<.>**
* For example, `0.5`, `1.`, `2.12`, and `123.0001`.
* **<.>****<(>****<)>**
* For example, `0.1(6)`, `1.(9)`, `123.00(1212)`.
The repeating portion of a decimal expansion is conventionally denoted within a pair of round brackets. For example:
* `1/6 = 0.16666666... = 0.1(6) = 0.1666(6) = 0.166(66)`.
**Example 1:**
**Input:** s = "0.(52)", t = "0.5(25)"
**Output:** true
**Explanation:** Because "0.(52)" represents 0.52525252..., and "0.5(25)" represents 0.52525252525..... , the strings represent the same number.
**Example 2:**
**Input:** s = "0.1666(6)", t = "0.166(66)"
**Output:** true
**Example 3:**
**Input:** s = "0.9(9)", t = "1."
**Output:** true
**Explanation:** "0.9(9)" represents 0.999999999... repeated forever, which equals 1. [[See this link for an explanation.](https://en.wikipedia.org/wiki/0.999...)] "1." represents the number 1, which is formed correctly: (IntegerPart) = "1" and (NonRepeatingPart) = "".
**Constraints:**
* Each part consists only of digits.
* The `` does not have leading zeros (except for the zero itself).
* `1 <= .length <= 4`
* `0 <= .length <= 4`
* `1 <= .length <= 4`