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Kotlin-based LeetCode algorithm problem solutions, regularly updated
package g1101_1200.s1187_make_array_strictly_increasing
// #Hard #Array #Dynamic_Programming #Binary_Search
// #2023_05_25_Time_308_ms_(100.00%)_Space_41.1_MB_(100.00%)
class Solution {
fun makeArrayIncreasing(arr1: IntArray, arr2: IntArray): Int {
arr2.sort()
var start = 0
for (i in arr2.indices) {
if (arr2[i] != arr2[start]) {
arr2[++start] = arr2[i]
}
}
val l2 = start + 1
val dp = IntArray(l2 + 2)
for (i in arr1.indices) {
var noChange = dp[dp.size - 1]
if (i > 0 && arr1[i - 1] >= arr1[i]) {
noChange = -1
}
for (j in dp.size - 2 downTo 1) {
if (arr2[j - 1] < arr1[i] && dp[j] != -1) {
noChange = if (noChange == -1) dp[j] else Math.min(noChange, dp[j])
}
if (dp[j - 1] != -1) {
dp[j] = 1 + dp[j - 1]
} else {
dp[j] = -1
}
if (i > 0 && arr1[i - 1] < arr2[j - 1] && dp[dp.size - 1] >= 0) {
dp[j] = if (dp[j] == -1) dp[dp.size - 1] + 1 else Math.min(dp[j], dp[dp.size - 1] + 1)
}
}
dp[0] = -1
dp[dp.size - 1] = noChange
}
var res = -1
for (num in dp) {
if (num != -1) {
res = if (res == -1) num else Math.min(res, num)
}
}
return res
}
}
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