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Kotlin-based LeetCode algorithm problem solutions, regularly updated
1187\. Make Array Strictly Increasing
Hard
Given two integer arrays `arr1` and `arr2`, return the minimum number of operations (possibly zero) needed to make `arr1` strictly increasing.
In one operation, you can choose two indices `0 <= i < arr1.length` and `0 <= j < arr2.length` and do the assignment `arr1[i] = arr2[j]`.
If there is no way to make `arr1` strictly increasing, return `-1`.
**Example 1:**
**Input:** arr1 = [1,5,3,6,7], arr2 = [1,3,2,4]
**Output:** 1
**Explanation:** Replace `5` with `2`, then `arr1 = [1, 2, 3, 6, 7]`.
**Example 2:**
**Input:** arr1 = [1,5,3,6,7], arr2 = [4,3,1]
**Output:** 2
**Explanation:** Replace `5` with `3` and then replace `3` with `4`. `arr1 = [1, 3, 4, 6, 7]`.
**Example 3:**
**Input:** arr1 = [1,5,3,6,7], arr2 = [1,6,3,3]
**Output:** -1
**Explanation:** You can't make `arr1` strictly increasing.
**Constraints:**
* `1 <= arr1.length, arr2.length <= 2000`
* `0 <= arr1[i], arr2[i] <= 10^9`