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Kotlin-based LeetCode algorithm problem solutions, regularly updated
package g1601_1700.s1627_graph_connectivity_with_threshold
// #Hard #Array #Math #Union_Find #2023_06_16_Time_703_ms_(100.00%)_Space_87.8_MB_(100.00%)
class Solution {
fun areConnected(n: Int, threshold: Int, queries: Array): List {
if (n < 1 || queries.isEmpty()) {
return ArrayList()
}
var j: Int
var k: Int
var x: Int
val set = DisjointSetUnion(n + 1)
val edges = queries.size
var i: Int = threshold + 1
while (i <= n) {
k = n / i
x = i
j = 2
while (j <= k) {
x += i
set.union(i, x)
j++
}
i++
}
val result: MutableList = ArrayList(edges)
for (query in queries) {
result.add(set.find(query[0]) == set.find(query[1]))
}
return result
}
private class DisjointSetUnion(n: Int) {
private val rank: IntArray
private val parent: IntArray
init {
rank = IntArray(n)
parent = IntArray(n)
for (i in 0 until n) {
rank[i] = 1
parent[i] = i
}
}
fun find(u: Int): Int {
var x = u
while (x != parent[x]) {
x = parent[x]
}
parent[u] = x
return x
}
fun union(u: Int, v: Int) {
if (u != v) {
val x = find(u)
val y = find(v)
if (x != y) {
if (rank[x] > rank[y]) {
rank[x] += rank[y]
parent[y] = x
} else {
rank[y] += rank[x]
parent[x] = y
}
}
}
}
}
}
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