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Kotlin-based LeetCode algorithm problem solutions, regularly updated
1771\. Maximize Palindrome Length From Subsequences
Hard
You are given two strings, `word1` and `word2`. You want to construct a string in the following manner:
* Choose some **non-empty** subsequence `subsequence1` from `word1`.
* Choose some **non-empty** subsequence `subsequence2` from `word2`.
* Concatenate the subsequences: `subsequence1 + subsequence2`, to make the string.
Return _the **length** of the longest **palindrome** that can be constructed in the described manner._ If no palindromes can be constructed, return `0`.
A **subsequence** of a string `s` is a string that can be made by deleting some (possibly none) characters from `s` without changing the order of the remaining characters.
A **palindrome** is a string that reads the same forward as well as backward.
**Example 1:**
**Input:** word1 = "cacb", word2 = "cbba"
**Output:** 5
**Explanation:** Choose "ab" from word1 and "cba" from word2 to make "abcba", which is a palindrome.
**Example 2:**
**Input:** word1 = "ab", word2 = "ab"
**Output:** 3
**Explanation:** Choose "ab" from word1 and "a" from word2 to make "aba", which is a palindrome.
**Example 3:**
**Input:** word1 = "aa", word2 = "bb"
**Output:** 0
**Explanation:** You cannot construct a palindrome from the described method, so return 0.
**Constraints:**
* `1 <= word1.length, word2.length <= 1000`
* `word1` and `word2` consist of lowercase English letters.