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Kotlin-based LeetCode algorithm problem solutions, regularly updated
1774\. Closest Dessert Cost
Medium
You would like to make dessert and are preparing to buy the ingredients. You have `n` ice cream base flavors and `m` types of toppings to choose from. You must follow these rules when making your dessert:
* There must be **exactly one** ice cream base.
* You can add **one or more** types of topping or have no toppings at all.
* There are **at most two** of **each type** of topping.
You are given three inputs:
* `baseCosts`, an integer array of length `n`, where each `baseCosts[i]` represents the price of the ith
ice cream base flavor.
* `toppingCosts`, an integer array of length `m`, where each `toppingCosts[i]` is the price of **one** of the ith
topping.
* `target`, an integer representing your target price for dessert.
You want to make a dessert with a total cost as close to `target` as possible.
Return _the closest possible cost of the dessert to_ `target`. If there are multiple, return _the **lower** one._
**Example 1:**
**Input:** baseCosts = [1,7], toppingCosts = [3,4], target = 10
**Output:** 10
**Explanation:** Consider the following combination (all 0-indexed):
- Choose base 1: cost 7
- Take 1 of topping 0: cost 1 x 3 = 3
- Take 0 of topping 1: cost 0 x 4 = 0
Total: 7 + 3 + 0 = 10.
**Example 2:**
**Input:** baseCosts = [2,3], toppingCosts = [4,5,100], target = 18
**Output:** 17
**Explanation:** Consider the following combination (all 0-indexed): - Choose base 1: cost 3 - Take 1 of topping 0: cost 1 x 4 = 4 - Take 2 of topping 1: cost 2 x 5 = 10 - Take 0 of topping 2: cost 0 x 100 = 0 Total: 3 + 4 + 10 + 0 = 17. You cannot make a dessert with a total cost of 18.
**Example 3:**
**Input:** baseCosts = [3,10], toppingCosts = [2,5], target = 9
**Output:** 8
**Explanation:** It is possible to make desserts with cost 8 and 10. Return 8 as it is the lower cost.
**Constraints:**
* `n == baseCosts.length`
* `m == toppingCosts.length`
* `1 <= n, m <= 10`
* 1 <= baseCosts[i], toppingCosts[i] <= 104
* 1 <= target <= 104