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Kotlin-based LeetCode algorithm problem solutions, regularly updated
1800\. Maximum Ascending Subarray Sum
Easy
Given an array of positive integers `nums`, return the _maximum possible sum of an **ascending** subarray in_ `nums`.
A subarray is defined as a contiguous sequence of numbers in an array.
A subarray [numsl, numsl+1, ..., numsr-1, numsr]
is **ascending** if for all `i` where `l <= i < r`, numsi < numsi+1
. Note that a subarray of size `1` is **ascending**.
**Example 1:**
**Input:** nums = [10,20,30,5,10,50]
**Output:** 65
**Explanation:** [5,10,50] is the ascending subarray with the maximum sum of 65.
**Example 2:**
**Input:** nums = [10,20,30,40,50]
**Output:** 150
**Explanation:** [10,20,30,40,50] is the ascending subarray with the maximum sum of 150.
**Example 3:**
**Input:** nums = [12,17,15,13,10,11,12]
**Output:** 33
**Explanation:** [10,11,12] is the ascending subarray with the maximum sum of 33.
**Constraints:**
* `1 <= nums.length <= 100`
* `1 <= nums[i] <= 100`