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Kotlin-based LeetCode algorithm problem solutions, regularly updated
1952\. Three Divisors
Easy
Given an integer `n`, return `true` _if_ `n` _has **exactly three positive divisors**. Otherwise, return_ `false`.
An integer `m` is a **divisor** of `n` if there exists an integer `k` such that `n = k * m`.
**Example 1:**
**Input:** n = 2
**Output:** false
**Explantion:** 2 has only two divisors: 1 and 2.
**Example 2:**
**Input:** n = 4
**Output:** true
**Explantion:** 4 has three divisors: 1, 2, and 4.
**Constraints:**
* 1 <= n <= 104