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Kotlin-based LeetCode algorithm problem solutions, regularly updated
2363\. Merge Similar Items
Easy
You are given two 2D integer arrays, `items1` and `items2`, representing two sets of items. Each array `items` has the following properties:
* items[i] = [valuei, weighti]
where valuei
represents the **value** and weighti
represents the **weight** of the ith
item.
* The value of each item in `items` is **unique**.
Return _a 2D integer array_ `ret` _where_ ret[i] = [valuei, weighti]
_,_ _with_ weighti
_being the **sum of weights** of all items with value_ valuei
.
**Note:** `ret` should be returned in **ascending** order by value.
**Example 1:**
**Input:** items1 = [[1,1],[4,5],[3,8]], items2 = [[3,1],[1,5]]
**Output:** [[1,6],[3,9],[4,5]]
**Explanation:**
The item with value = 1 occurs in items1 with weight = 1 and in items2 with weight = 5, total weight = 1 + 5 = 6.
The item with value = 3 occurs in items1 with weight = 8 and in items2 with weight = 1, total weight = 8 + 1 = 9.
The item with value = 4 occurs in items1 with weight = 5, total weight = 5.
Therefore, we return [[1,6],[3,9],[4,5]].
**Example 2:**
**Input:** items1 = [[1,1],[3,2],[2,3]], items2 = [[2,1],[3,2],[1,3]]
**Output:** [[1,4],[2,4],[3,4]]
**Explanation:**
The item with value = 1 occurs in items1 with weight = 1 and in items2 with weight = 3, total weight = 1 + 3 = 4.
The item with value = 2 occurs in items1 with weight = 3 and in items2 with weight = 1, total weight = 3 + 1 = 4.
The item with value = 3 occurs in items1 with weight = 2 and in items2 with weight = 2, total weight = 2 + 2 = 4. Therefore, we return [[1,4],[2,4],[3,4]].
**Example 3:**
**Input:** items1 = [[1,3],[2,2]], items2 = [[7,1],[2,2],[1,4]]
**Output:** [[1,7],[2,4],[7,1]]
**Explanation:**
The item with value = 1 occurs in items1 with weight = 3 and in items2 with weight = 4, total weight = 3 + 4 = 7.
The item with value = 2 occurs in items1 with weight = 2 and in items2 with weight = 2, total weight = 2 + 2 = 4.
The item with value = 7 occurs in items2 with weight = 1, total weight = 1.
Therefore, we return [[1,7],[2,4],[7,1]].
**Constraints:**
* `1 <= items1.length, items2.length <= 1000`
* `items1[i].length == items2[i].length == 2`
* 1 <= valuei, weighti <= 1000
* Each valuei
in `items1` is **unique**.
* Each valuei
in `items2` is **unique**.