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Kotlin-based LeetCode algorithm problem solutions, regularly updated
2364\. Count Number of Bad Pairs
Medium
You are given a **0-indexed** integer array `nums`. A pair of indices `(i, j)` is a **bad pair** if `i < j` and `j - i != nums[j] - nums[i]`.
Return _the total number of **bad pairs** in_ `nums`.
**Example 1:**
**Input:** nums = [4,1,3,3]
**Output:** 5
**Explanation:**
The pair (0, 1) is a bad pair since 1 - 0 != 1 - 4.
The pair (0, 2) is a bad pair since 2 - 0 != 3 - 4, 2 != -1.
The pair (0, 3) is a bad pair since 3 - 0 != 3 - 4, 3 != -1.
The pair (1, 2) is a bad pair since 2 - 1 != 3 - 1, 1 != 2.
The pair (2, 3) is a bad pair since 3 - 2 != 3 - 3, 1 != 0.
There are a total of 5 bad pairs, so we return 5.
**Example 2:**
**Input:** nums = [1,2,3,4,5]
**Output:** 0
**Explanation:** There are no bad pairs.
**Constraints:**
* 1 <= nums.length <= 105
* 1 <= nums[i] <= 109