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Kotlin-based LeetCode algorithm problem solutions, regularly updated
2381\. Shifting Letters II
Medium
You are given a string `s` of lowercase English letters and a 2D integer array `shifts` where shifts[i] = [starti, endi, directioni]
. For every `i`, **shift** the characters in `s` from the index starti
to the index endi
(**inclusive**) forward if directioni = 1
, or shift the characters backward if directioni = 0
.
Shifting a character **forward** means replacing it with the **next** letter in the alphabet (wrapping around so that `'z'` becomes `'a'`). Similarly, shifting a character **backward** means replacing it with the **previous** letter in the alphabet (wrapping around so that `'a'` becomes `'z'`).
Return _the final string after all such shifts to_ `s` _are applied_.
**Example 1:**
**Input:** s = "abc", shifts = [[0,1,0],[1,2,1],[0,2,1]]
**Output:** "ace"
**Explanation:** Firstly, shift the characters from index 0 to index 1 backward. Now s = "zac".
Secondly, shift the characters from index 1 to index 2 forward. Now s = "zbd".
Finally, shift the characters from index 0 to index 2 forward. Now s = "ace".
**Example 2:**
**Input:** s = "dztz", shifts = [[0,0,0],[1,1,1]]
**Output:** "catz"
**Explanation:** Firstly, shift the characters from index 0 to index 0 backward. Now s = "cztz".
Finally, shift the characters from index 1 to index 1 forward. Now s = "catz".
**Constraints:**
* 1 <= s.length, shifts.length <= 5 * 104
* `shifts[i].length == 3`
* 0 <= starti <= endi < s.length
* 0 <= directioni <= 1
* `s` consists of lowercase English letters.