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Kotlin-based LeetCode algorithm problem solutions, regularly updated
2453\. Destroy Sequential Targets
Medium
You are given a **0-indexed** array `nums` consisting of positive integers, representing targets on a number line. You are also given an integer `space`.
You have a machine which can destroy targets. **Seeding** the machine with some `nums[i]` allows it to destroy all targets with values that can be represented as `nums[i] + c * space`, where `c` is any non-negative integer. You want to destroy the **maximum** number of targets in `nums`.
Return _the **minimum value** of_ `nums[i]` _you can seed the machine with to destroy the maximum number of targets._
**Example 1:**
**Input:** nums = [3,7,8,1,1,5], space = 2
**Output:** 1
**Explanation:** If we seed the machine with nums[3], then we destroy all targets equal to 1,3,5,7,9,... In this case, we would destroy 5 total targets (all except for nums[2]). It is impossible to destroy more than 5 targets, so we return nums[3].
**Example 2:**
**Input:** nums = [1,3,5,2,4,6], space = 2
**Output:** 1
**Explanation:** Seeding the machine with nums[0], or nums[3] destroys 3 targets. It is not possible to destroy more than 3 targets. Since nums[0] is the minimal integer that can destroy 3 targets, we return 1.
**Example 3:**
**Input:** nums = [6,2,5], space = 100
**Output:** 2
**Explanation:** Whatever initial seed we select, we can only destroy 1 target. The minimal seed is nums[1].
**Constraints:**
* 1 <= nums.length <= 105
* 1 <= nums[i] <= 109
* 1 <= space <= 109