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Kotlin-based LeetCode algorithm problem solutions, regularly updated
2514\. Count Anagrams
Hard
You are given a string `s` containing one or more words. Every consecutive pair of words is separated by a single space `' '`.
A string `t` is an **anagram** of string `s` if the ith
word of `t` is a **permutation** of the ith
word of `s`.
* For example, `"acb dfe"` is an anagram of `"abc def"`, but `"def cab"` and `"adc bef"` are not.
Return _the number of **distinct anagrams** of_ `s`. Since the answer may be very large, return it **modulo** 109 + 7
.
**Example 1:**
**Input:** s = "too hot"
**Output:** 18
**Explanation:** Some of the anagrams of the given string are "too hot", "oot hot", "oto toh", "too toh", and "too oht".
**Example 2:**
**Input:** s = "aa"
**Output:** 1
**Explanation:** There is only one anagram possible for the given string.
**Constraints:**
* 1 <= s.length <= 105
* `s` consists of lowercase English letters and spaces `' '`.
* There is single space between consecutive words.