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Kotlin-based LeetCode algorithm problem solutions, regularly updated
2544\. Alternating Digit Sum
Easy
You are given a positive integer `n`. Each digit of `n` has a sign according to the following rules:
* The **most significant digit** is assigned a **positive** sign.
* Each other digit has an opposite sign to its adjacent digits.
Return _the sum of all digits with their corresponding sign_.
**Example 1:**
**Input:** n = 521
**Output:** 4
**Explanation:** (+5) + (-2) + (+1) = 4.
**Example 2:**
**Input:** n = 111
**Output:** 1
**Explanation:** (+1) + (-1) + (+1) = 1.
**Example 3:**
**Input:** n = 886996
**Output:** 0
**Explanation:** (+8) + (-8) + (+6) + (-9) + (+9) + (-6) = 0.
**Constraints:**
* 1 <= n <= 109