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Kotlin-based LeetCode algorithm problem solutions, regularly updated
2551\. Put Marbles in Bags
Hard
You have `k` bags. You are given a **0-indexed** integer array `weights` where `weights[i]` is the weight of the ith
marble. You are also given the integer `k.`
Divide the marbles into the `k` bags according to the following rules:
* No bag is empty.
* If the ith
marble and jth
marble are in a bag, then all marbles with an index between the ith
and jth
indices should also be in that same bag.
* If a bag consists of all the marbles with an index from `i` to `j` inclusively, then the cost of the bag is `weights[i] + weights[j]`.
The **score** after distributing the marbles is the sum of the costs of all the `k` bags.
Return _the **difference** between the **maximum** and **minimum** scores among marble distributions_.
**Example 1:**
**Input:** weights = [1,3,5,1], k = 2
**Output:** 4
**Explanation:**
The distribution [1],[3,5,1] results in the minimal score of (1+1) + (3+1) = 6.
The distribution [1,3],[5,1], results in the maximal score of (1+3) + (5+1) = 10.
Thus, we return their difference 10 - 6 = 4.
**Example 2:**
**Input:** weights = [1, 3], k = 2
**Output:** 0
**Explanation:**
The only distribution possible is [1],[3].
Since both the maximal and minimal score are the same, we return 0.
**Constraints:**
* 1 <= k <= weights.length <= 105
* 1 <= weights[i] <= 109