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Kotlin-based LeetCode algorithm problem solutions, regularly updated
73\. Set Matrix Zeroes
Medium
Given an `m x n` integer matrix `matrix`, if an element is `0`, set its entire row and column to `0`'s.
You must do it [in place](https://en.wikipedia.org/wiki/In-place_algorithm).
**Example 1:**
![](https://assets.leetcode.com/uploads/2020/08/17/mat1.jpg)
**Input:** matrix = [[1,1,1],[1,0,1],[1,1,1]]
**Output:** [[1,0,1],[0,0,0],[1,0,1]]
**Example 2:**
![](https://assets.leetcode.com/uploads/2020/08/17/mat2.jpg)
**Input:** matrix = [[0,1,2,0],[3,4,5,2],[1,3,1,5]]
**Output:** [[0,0,0,0],[0,4,5,0],[0,3,1,0]]
**Constraints:**
* `m == matrix.length`
* `n == matrix[0].length`
* `1 <= m, n <= 200`
* -231 <= matrix[i][j] <= 231 - 1
**Follow up:**
* A straightforward solution using `O(mn)` space is probably a bad idea.
* A simple improvement uses `O(m + n)` space, but still not the best solution.
* Could you devise a constant space solution?