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Kotlin-based LeetCode algorithm problem solutions, regularly updated
144\. Binary Tree Preorder Traversal
Easy
Given the `root` of a binary tree, return _the preorder traversal of its nodes' values_.
**Example 1:**
![](https://assets.leetcode.com/uploads/2020/09/15/inorder_1.jpg)
**Input:** root = [1,null,2,3]
**Output:** [1,2,3]
**Example 2:**
**Input:** root = []
**Output:** []
**Example 3:**
**Input:** root = [1]
**Output:** [1]
**Constraints:**
* The number of nodes in the tree is in the range `[0, 100]`.
* `-100 <= Node.val <= 100`
**Follow up:** Recursive solution is trivial, could you do it iteratively?