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Kotlin-based LeetCode algorithm problem solutions, regularly updated

There is a newer version: 1.30

528\. Random Pick with Weight

Medium

You are given a **0-indexed** array of positive integers `w` where `w[i]` describes the **weight** of the i^th index.

You need to implement the function `pickIndex()`, which **randomly** picks an index in the range `[0, w.length - 1]` (**inclusive**) and returns it. The **probability** of picking an index `i` is `w[i] / sum(w)`.

*   For example, if `w = [1, 3]`, the probability of picking index `0` is `1 / (1 + 3) = 0.25` (i.e., `25%`), and the probability of picking index `1` is `3 / (1 + 3) = 0.75` (i.e., `75%`).

**Example 1:**

**Input** ["Solution","pickIndex"] [[[1]],[]]

**Output:** [null,0]

**Explanation:**

    Solution solution = new Solution([1]); 
    solution.pickIndex(); // return 0. The only option is to return 0 since there is only one element in w.

**Example 2:**

**Input**

    ["Solution","pickIndex","pickIndex","pickIndex","pickIndex","pickIndex"]
    [[[1,3]],[],[],[],[],[]]

**Output:** [null,1,1,1,1,0]

**Explanation:**

    Solution solution = new Solution([1, 3]); 
    solution.pickIndex(); // return 1. It is returning the second element (index = 1) that has a probability of 3/4. 
    solution.pickIndex(); // return 1 
    solution.pickIndex(); // return 1 
    solution.pickIndex(); // return 1 
    solution.pickIndex(); // return 0. It is returning the first element (index = 0) that has a probability of 1/4. 

    Since this is a randomization problem, multiple answers are allowed. 
    All of the following outputs can be considered correct: 
    [null,1,1,1,1,0] 
    [null,1,1,1,1,1] 
    [null,1,1,1,0,0] 
    [null,1,1,1,0,1] 
    [null,1,0,1,0,0] 
    ...... 
    and so on.

**Constraints:**

*   1 <= w.length <= 10⁴
*   1 <= w[i] <= 10⁵
*   `pickIndex` will be called at most 10⁴ times.