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Kotlin-based LeetCode algorithm problem solutions, regularly updated
542\. 01 Matrix
Medium
Given an `m x n` binary matrix `mat`, return _the distance of the nearest_ `0` _for each cell_.
The distance between two adjacent cells is `1`.
**Example 1:**
![](https://assets.leetcode.com/uploads/2021/04/24/01-1-grid.jpg)
**Input:** mat = [[0,0,0],[0,1,0],[0,0,0]]
**Output:** [[0,0,0],[0,1,0],[0,0,0]]
**Example 2:**
![](https://assets.leetcode.com/uploads/2021/04/24/01-2-grid.jpg)
**Input:** mat = [[0,0,0],[0,1,0],[1,1,1]]
**Output:** [[0,0,0],[0,1,0],[1,2,1]]
**Constraints:**
* `m == mat.length`
* `n == mat[i].length`
* 1 <= m, n <= 104
* 1 <= m * n <= 104
* `mat[i][j]` is either `0` or `1`.
* There is at least one `0` in `mat`.