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Kotlin-based LeetCode algorithm problem solutions, regularly updated
561\. Array Partition
Easy
Given an integer array `nums` of `2n` integers, group these integers into `n` pairs (a1, b1), (a2, b2), ..., (an, bn)
such that the sum of min(ai, bi)
for all `i` is **maximized**. Return _the maximized sum_.
**Example 1:**
**Input:** nums = [1,4,3,2]
**Output:** 4
**Explanation:** All possible pairings (ignoring the ordering of elements) are:
1. (1, 4), (2, 3) -> min(1, 4) + min(2, 3) = 1 + 2 = 3
2. (1, 3), (2, 4) -> min(1, 3) + min(2, 4) = 1 + 2 = 3
3. (1, 2), (3, 4) -> min(1, 2) + min(3, 4) = 1 + 3 = 4 So the maximum possible sum is 4.
**Example 2:**
**Input:** nums = [6,2,6,5,1,2]
**Output:** 9
**Explanation:** The optimal pairing is (2, 1), (2, 5), (6, 6). min(2, 1) + min(2, 5) + min(6, 6) = 1 + 2 + 6 = 9.
**Constraints:**
* 1 <= n <= 104
* `nums.length == 2 * n`
* -104 <= nums[i] <= 104