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Kotlin-based LeetCode algorithm problem solutions, regularly updated
645\. Set Mismatch
Easy
You have a set of integers `s`, which originally contains all the numbers from `1` to `n`. Unfortunately, due to some error, one of the numbers in `s` got duplicated to another number in the set, which results in **repetition of one** number and **loss of another** number.
You are given an integer array `nums` representing the data status of this set after the error.
Find the number that occurs twice and the number that is missing and return _them in the form of an array_.
**Example 1:**
**Input:** nums = [1,2,2,4]
**Output:** [2,3]
**Example 2:**
**Input:** nums = [1,1]
**Output:** [1,2]
**Constraints:**
* 2 <= nums.length <= 104
* 1 <= nums[i] <= 104