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Kotlin-based LeetCode algorithm problem solutions, regularly updated
648\. Replace Words
Medium
In English, we have a concept called **root**, which can be followed by some other word to form another longer word - let's call this word **successor**. For example, when the **root** `"an"` is followed by the **successor** word `"other"`, we can form a new word `"another"`.
Given a `dictionary` consisting of many **roots** and a `sentence` consisting of words separated by spaces, replace all the **successors** in the sentence with the **root** forming it. If a **successor** can be replaced by more than one **root**, replace it with the **root** that has **the shortest length**.
Return _the `sentence`_ after the replacement.
**Example 1:**
**Input:** dictionary = ["cat","bat","rat"], sentence = "the cattle was rattled by the battery"
**Output:** "the cat was rat by the bat"
**Example 2:**
**Input:** dictionary = ["a","b","c"], sentence = "aadsfasf absbs bbab cadsfafs"
**Output:** "a a b c"
**Constraints:**
* `1 <= dictionary.length <= 1000`
* `1 <= dictionary[i].length <= 100`
* `dictionary[i]` consists of only lower-case letters.
* 1 <= sentence.length <= 106
* `sentence` consists of only lower-case letters and spaces.
* The number of words in `sentence` is in the range `[1, 1000]`
* The length of each word in `sentence` is in the range `[1, 1000]`
* Every two consecutive words in `sentence` will be separated by exactly one space.
* `sentence` does not have leading or trailing spaces.