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Kotlin-based LeetCode algorithm problem solutions, regularly updated
697\. Degree of an Array
Easy
Given a non-empty array of non-negative integers `nums`, the **degree** of this array is defined as the maximum frequency of any one of its elements.
Your task is to find the smallest possible length of a (contiguous) subarray of `nums`, that has the same degree as `nums`.
**Example 1:**
**Input:** nums = [1,2,2,3,1]
**Output:** 2
**Explanation:** The input array has a degree of 2 because both elements 1 and 2 appear twice. Of the subarrays that have the same degree: [1, 2, 2, 3, 1], [1, 2, 2, 3], [2, 2, 3, 1], [1, 2, 2], [2, 2, 3], [2, 2] The shortest length is 2. So return 2.
**Example 2:**
**Input:** nums = [1,2,2,3,1,4,2]
**Output:** 6
**Explanation:** The degree is 3 because the element 2 is repeated 3 times. So [2,2,3,1,4,2] is the shortest subarray, therefore returning 6.
**Constraints:**
* `nums.length` will be between 1 and 50,000.
* `nums[i]` will be an integer between 0 and 49,999.