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Kotlin-based LeetCode algorithm problem solutions, regularly updated
766\. Toeplitz Matrix
Easy
Given an `m x n` `matrix`, return _`true` if the matrix is Toeplitz. Otherwise, return `false`._
A matrix is **Toeplitz** if every diagonal from top-left to bottom-right has the same elements.
**Example 1:**
![](https://assets.leetcode.com/uploads/2020/11/04/ex1.jpg)
**Input:** matrix = [[1,2,3,4],[5,1,2,3],[9,5,1,2]]
**Output:** true
**Explanation:** In the above grid, the diagonals are: "[9]", "[5, 5]", "[1, 1, 1]", "[2, 2, 2]", "[3, 3]", "[4]". In each diagonal all elements are the same, so the answer is True.
**Example 2:**
![](https://assets.leetcode.com/uploads/2020/11/04/ex2.jpg)
**Input:** matrix = [[1,2],[2,2]]
**Output:** false
**Explanation:** The diagonal "[1, 2]" has different elements.
**Constraints:**
* `m == matrix.length`
* `n == matrix[i].length`
* `1 <= m, n <= 20`
* `0 <= matrix[i][j] <= 99`
**Follow up:**
* What if the `matrix` is stored on disk, and the memory is limited such that you can only load at most one row of the matrix into the memory at once?
* What if the `matrix` is so large that you can only load up a partial row into the memory at once?