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Kotlin-based LeetCode algorithm problem solutions, regularly updated
788\. Rotated Digits
Medium
An integer `x` is a **good** if after rotating each digit individually by 180 degrees, we get a valid number that is different from `x`. Each digit must be rotated - we cannot choose to leave it alone.
A number is valid if each digit remains a digit after rotation. For example:
* `0`, `1`, and `8` rotate to themselves,
* `2` and `5` rotate to each other (in this case they are rotated in a different direction, in other words, `2` or `5` gets mirrored),
* `6` and `9` rotate to each other, and
* the rest of the numbers do not rotate to any other number and become invalid.
Given an integer `n`, return _the number of **good** integers in the range_ `[1, n]`.
**Example 1:**
**Input:** n = 10
**Output:** 4
**Explanation:** There are four good numbers in the range [1, 10] : 2, 5, 6, 9. Note that 1 and 10 are not good numbers, since they remain unchanged after rotating.
**Example 2:**
**Input:** n = 1
**Output:** 0
**Example 3:**
**Input:** n = 2
**Output:** 1
**Constraints:**
* 1 <= n <= 104