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Kotlin-based LeetCode algorithm problem solutions, regularly updated
802\. Find Eventual Safe States
Medium
There is a directed graph of `n` nodes with each node labeled from `0` to `n - 1`. The graph is represented by a **0-indexed** 2D integer array `graph` where `graph[i]` is an integer array of nodes adjacent to node `i`, meaning there is an edge from node `i` to each node in `graph[i]`.
A node is a **terminal node** if there are no outgoing edges. A node is a **safe node** if every possible path starting from that node leads to a **terminal node** (or another safe node).
Return _an array containing all the **safe nodes** of the graph_. The answer should be sorted in **ascending** order.
**Example 1:**
![Illustration of graph](https://s3-lc-upload.s3.amazonaws.com/uploads/2018/03/17/picture1.png)
**Input:** graph = [[1,2],[2,3],[5],[0],[5],[],[]]
**Output:** [2,4,5,6]
**Explanation:** The given graph is shown above. Nodes 5 and 6 are terminal nodes as there are no outgoing edges from either of them. Every path starting at nodes 2, 4, 5, and 6 all lead to either node 5 or 6.
**Example 2:**
**Input:** graph = [[1,2,3,4],[1,2],[3,4],[0,4],[]]
**Output:** [4]
**Explanation:** Only node 4 is a terminal node, and every path starting at node 4 leads to node 4.
**Constraints:**
* `n == graph.length`
* 1 <= n <= 104
* `0 <= graph[i].length <= n`
* `0 <= graph[i][j] <= n - 1`
* `graph[i]` is sorted in a strictly increasing order.
* The graph may contain self-loops.
* The number of edges in the graph will be in the range [1, 4 * 104]
.