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Kotlin-based LeetCode algorithm problem solutions, regularly updated
844\. Backspace String Compare
Easy
Given two strings `s` and `t`, return `true` _if they are equal when both are typed into empty text editors_. `'#'` means a backspace character.
Note that after backspacing an empty text, the text will continue empty.
**Example 1:**
**Input:** s = "ab#c", t = "ad#c"
**Output:** true
**Explanation:** Both s and t become "ac".
**Example 2:**
**Input:** s = "ab##", t = "c#d#"
**Output:** true
**Explanation:** Both s and t become "".
**Example 3:**
**Input:** s = "a#c", t = "b"
**Output:** false
**Explanation:** s becomes "c" while t becomes "b".
**Constraints:**
* `1 <= s.length, t.length <= 200`
* `s` and `t` only contain lowercase letters and `'#'` characters.
**Follow up:** Can you solve it in `O(n)` time and `O(1)` space?