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Kotlin-based LeetCode algorithm problem solutions, regularly updated
966\. Vowel Spellchecker
Medium
Given a `wordlist`, we want to implement a spellchecker that converts a query word into a correct word.
For a given `query` word, the spell checker handles two categories of spelling mistakes:
* Capitalization: If the query matches a word in the wordlist (**case-insensitive**), then the query word is returned with the same case as the case in the wordlist.
* Example: `wordlist = ["yellow"]`, `query = "YellOw"`: `correct = "yellow"`
* Example: `wordlist = ["Yellow"]`, `query = "yellow"`: `correct = "Yellow"`
* Example: `wordlist = ["yellow"]`, `query = "yellow"`: `correct = "yellow"`
* Vowel Errors: If after replacing the vowels `('a', 'e', 'i', 'o', 'u')` of the query word with any vowel individually, it matches a word in the wordlist (**case-insensitive**), then the query word is returned with the same case as the match in the wordlist.
* Example: `wordlist = ["YellOw"]`, `query = "yollow"`: `correct = "YellOw"`
* Example: `wordlist = ["YellOw"]`, `query = "yeellow"`: `correct = ""` (no match)
* Example: `wordlist = ["YellOw"]`, `query = "yllw"`: `correct = ""` (no match)
In addition, the spell checker operates under the following precedence rules:
* When the query exactly matches a word in the wordlist (**case-sensitive**), you should return the same word back.
* When the query matches a word up to capitlization, you should return the first such match in the wordlist.
* When the query matches a word up to vowel errors, you should return the first such match in the wordlist.
* If the query has no matches in the wordlist, you should return the empty string.
Given some `queries`, return a list of words `answer`, where `answer[i]` is the correct word for `query = queries[i]`.
**Example 1:**
**Input:** wordlist = ["KiTe","kite","hare","Hare"], queries = ["kite","Kite","KiTe","Hare","HARE","Hear","hear","keti","keet","keto"]
**Output:** ["kite","KiTe","KiTe","Hare","hare","","","KiTe","","KiTe"]
**Example 2:**
**Input:** wordlist = ["yellow"], queries = ["YellOw"]
**Output:** ["yellow"]
**Constraints:**
* `1 <= wordlist.length, queries.length <= 5000`
* `1 <= wordlist[i].length, queries[i].length <= 7`
* `wordlist[i]` and `queries[i]` consist only of only English letters.