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Kotlin-based LeetCode algorithm problem solutions, regularly updated
1042\. Flower Planting With No Adjacent
Medium
You have `n` gardens, labeled from `1` to `n`, and an array `paths` where paths[i] = [xi, yi]
describes a bidirectional path between garden xi
to garden yi
. In each garden, you want to plant one of 4 types of flowers.
All gardens have **at most 3** paths coming into or leaving it.
Your task is to choose a flower type for each garden such that, for any two gardens connected by a path, they have different types of flowers.
Return _**any** such a choice as an array_ `answer`_, where_ `answer[i]` _is the type of flower planted in the_ (i+1)th
_garden. The flower types are denoted_ `1`_,_ `2`_,_ `3`_, or_ `4`_. It is guaranteed an answer exists._
**Example 1:**
**Input:** n = 3, paths = [[1,2],[2,3],[3,1]]
**Output:** [1,2,3]
**Explanation:**
Gardens 1 and 2 have different types.
Gardens 2 and 3 have different types.
Gardens 3 and 1 have different types.
Hence, [1,2,3] is a valid answer. Other valid answers include [1,2,4], [1,4,2], and [3,2,1].
**Example 2:**
**Input:** n = 4, paths = [[1,2],[3,4]]
**Output:** [1,2,1,2]
**Example 3:**
**Input:** n = 4, paths = [[1,2],[2,3],[3,4],[4,1],[1,3],[2,4]]
**Output:** [1,2,3,4]
**Constraints:**
* 1 <= n <= 104
* 0 <= paths.length <= 2 * 104
* `paths[i].length == 2`
* 1 <= xi, yi <= n
* xi != yi
* Every garden has **at most 3** paths coming into or leaving it.