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Kotlin-based LeetCode algorithm problem solutions, regularly updated
1345\. Jump Game IV
Hard
Given an array of integers `arr`, you are initially positioned at the first index of the array.
In one step you can jump from index `i` to index:
* `i + 1` where: `i + 1 < arr.length`.
* `i - 1` where: `i - 1 >= 0`.
* `j` where: `arr[i] == arr[j]` and `i != j`.
Return _the minimum number of steps_ to reach the **last index** of the array.
Notice that you can not jump outside of the array at any time.
**Example 1:**
**Input:** arr = [100,-23,-23,404,100,23,23,23,3,404]
**Output:** 3
**Explanation:** You need three jumps from index 0 --> 4 --> 3 --> 9. Note that index 9 is the last index of the array.
**Example 2:**
**Input:** arr = [7]
**Output:** 0
**Explanation:** Start index is the last index. You do not need to jump.
**Example 3:**
**Input:** arr = [7,6,9,6,9,6,9,7]
**Output:** 1
**Explanation:** You can jump directly from index 0 to index 7 which is last index of the array.
**Constraints:**
* 1 <= arr.length <= 5 * 104
* -108 <= arr[i] <= 108