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Kotlin-based LeetCode algorithm problem solutions, regularly updated
1408\. String Matching in an Array
Easy
Given an array of string `words`. Return all strings in `words` which is substring of another word in **any** order.
String `words[i]` is substring of `words[j]`, if can be obtained removing some characters to left and/or right side of `words[j]`.
**Example 1:**
**Input:** words = ["mass","as","hero","superhero"]
**Output:** ["as","hero"]
**Explanation:** "as" is substring of "mass" and "hero" is substring of "superhero". ["hero","as"] is also a valid answer.
**Example 2:**
**Input:** words = ["leetcode","et","code"]
**Output:** ["et","code"]
**Explanation:** "et", "code" are substring of "leetcode".
**Example 3:**
**Input:** words = ["blue","green","bu"]
**Output:** []
**Constraints:**
* `1 <= words.length <= 100`
* `1 <= words[i].length <= 30`
* `words[i]` contains only lowercase English letters.
* It's **guaranteed** that `words[i]` will be unique.