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Kotlin-based LeetCode algorithm problem solutions, regularly updated
1680\. Concatenation of Consecutive Binary Numbers
Medium
Given an integer `n`, return _the **decimal value** of the binary string formed by concatenating the binary representations of_ `1` _to_ `n` _in order, **modulo**_ 109 + 7
.
**Example 1:**
**Input:** n = 1
**Output:** 1
**Explanation:** "1" in binary corresponds to the decimal value 1.
**Example 2:**
**Input:** n = 3
**Output:** 27
**Explanation:** In binary, 1, 2, and 3 corresponds to "1", "10", and "11".
After concatenating them, we have "11011", which corresponds to the decimal value 27.
**Example 3:**
**Input:** n = 12
**Output:** 505379714
**Explanation:** The concatenation results in "1101110010111011110001001101010111100".
The decimal value of that is 118505380540.
After modulo 109 + 7, the result is 505379714.
**Constraints:**
* 1 <= n <= 105