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Kotlin-based LeetCode algorithm problem solutions, regularly updated
1773\. Count Items Matching a Rule
Easy
You are given an array `items`, where each items[i] = [typei, colori, namei]
describes the type, color, and name of the ith
item. You are also given a rule represented by two strings, `ruleKey` and `ruleValue`.
The ith
item is said to match the rule if **one** of the following is true:
* `ruleKey == "type"` and ruleValue == typei
.
* `ruleKey == "color"` and ruleValue == colori
.
* `ruleKey == "name"` and ruleValue == namei
.
Return _the number of items that match the given rule_.
**Example 1:**
**Input:** items = [["phone","blue","pixel"],["computer","silver","lenovo"],["phone","gold","iphone"]], ruleKey = "color", ruleValue = "silver"
**Output:** 1
**Explanation:** There is only one item matching the given rule, which is ["computer","silver","lenovo"].
**Example 2:**
**Input:** items = [["phone","blue","pixel"],["computer","silver","phone"],["phone","gold","iphone"]], ruleKey = "type", ruleValue = "phone"
**Output:** 2
**Explanation:** There are only two items matching the given rule, which are ["phone","blue","pixel"] and ["phone","gold","iphone"]. Note that the item ["computer","silver","phone"] does not match.
**Constraints:**
* 1 <= items.length <= 104
* 1 <= typei.length, colori.length, namei.length, ruleValue.length <= 10
* `ruleKey` is equal to either `"type"`, `"color"`, or `"name"`.
* All strings consist only of lowercase letters.