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Kotlin-based LeetCode algorithm problem solutions, regularly updated
1862\. Sum of Floored Pairs
Hard
Given an integer array `nums`, return the sum of `floor(nums[i] / nums[j])` for all pairs of indices `0 <= i, j < nums.length` in the array. Since the answer may be too large, return it **modulo** 109 + 7
.
The `floor()` function returns the integer part of the division.
**Example 1:**
**Input:** nums = [2,5,9]
**Output:** 10
**Explanation:**
floor(2 / 5) = floor(2 / 9) = floor(5 / 9) = 0
floor(2 / 2) = floor(5 / 5) = floor(9 / 9) = 1
floor(5 / 2) = 2
floor(9 / 2) = 4
floor(9 / 5) = 1
We calculate the floor of the division for every pair of indices in the array then sum them up.
**Example 2:**
**Input:** nums = [7,7,7,7,7,7,7]
**Output:** 49
**Constraints:**
* 1 <= nums.length <= 105
* 1 <= nums[i] <= 105