• Home
• com.github.javadev
• leetcode-in-kotlin
• 1.21
• source code
• readme.md

×

Project download

Many resources are needed to download a project. Please understand that we have to compensate our server costs. Thank you in advance.
Project price only 1 $

You can buy this project and download/modify it how often you want.

g1901_2000.s1911_maximum_alternating_subsequence_sum.readme.md Maven / Gradle / Ivy

1911\. Maximum Alternating Subsequence Sum

Medium

The **alternating sum** of a **0-indexed** array is defined as the **sum** of the elements at **even** indices **minus** the **sum** of the elements at **odd** indices.

*   For example, the alternating sum of `[4,2,5,3]` is `(4 + 5) - (2 + 3) = 4`.

Given an array `nums`, return _the **maximum alternating sum** of any subsequence of_ `nums` _(after **reindexing** the elements of the subsequence)_.

A **subsequence** of an array is a new array generated from the original array by deleting some elements (possibly none) without changing the remaining elements' relative order. For example, `[2,7,4]` is a subsequence of `[4,2,3,7,2,1,4]` (the underlined elements), while `[2,4,2]` is not.

**Example 1:**

**Input:** nums = [4,2,5,3]

**Output:** 7

**Explanation:** It is optimal to choose the subsequence [4,2,5] with alternating sum (4 + 5) - 2 = 7. 

**Example 2:**

**Input:** nums = [5,6,7,8]

**Output:** 8

**Explanation:** It is optimal to choose the subsequence [8] with alternating sum 8. 

**Example 3:**

**Input:** nums = [6,2,1,2,4,5]

**Output:** 10

**Explanation:** It is optimal to choose the subsequence [6,1,5] with alternating sum (6 + 5) - 1 = 10. 

**Constraints:**

*   1 <= nums.length <= 105
*   1 <= nums[i] <= 105