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Kotlin-based LeetCode algorithm problem solutions, regularly updated
2016\. Maximum Difference Between Increasing Elements
Easy
Given a **0-indexed** integer array `nums` of size `n`, find the **maximum difference** between `nums[i]` and `nums[j]` (i.e., `nums[j] - nums[i]`), such that `0 <= i < j < n` and `nums[i] < nums[j]`.
Return _the **maximum difference**._ If no such `i` and `j` exists, return `-1`.
**Example 1:**
**Input:** nums = [7,**1**,**5**,4]
**Output:** 4
**Explanation:**
The maximum difference occurs with i = 1 and j = 2, nums[j] - nums[i] = 5 - 1 = 4.
Note that with i = 1 and j = 0, the difference nums[j] - nums[i] = 7 - 1 = 6, but i > j, so it is not valid.
**Example 2:**
**Input:** nums = [9,4,3,2]
**Output:** -1
**Explanation:**
There is no i and j such that i < j and nums[i] < nums[j].
**Example 3:**
**Input:** nums = [**1**,5,2,**10**]
**Output:** 9
**Explanation:**
The maximum difference occurs with i = 0 and j = 3, nums[j] - nums[i] = 10 - 1 = 9.
**Constraints:**
* `n == nums.length`
* `2 <= n <= 1000`
* 1 <= nums[i] <= 109