g2001_2100.s2059_minimum_operations_to_convert_number.readme.md Maven / Gradle / Ivy
Go to download
Show more of this group Show more artifacts with this name
Show all versions of leetcode-in-kotlin Show documentation
Show all versions of leetcode-in-kotlin Show documentation
Kotlin-based LeetCode algorithm problem solutions, regularly updated
2059\. Minimum Operations to Convert Number
Medium
You are given a **0-indexed** integer array `nums` containing **distinct** numbers, an integer `start`, and an integer `goal`. There is an integer `x` that is initially set to `start`, and you want to perform operations on `x` such that it is converted to `goal`. You can perform the following operation repeatedly on the number `x`:
If `0 <= x <= 1000`, then for any index `i` in the array (`0 <= i < nums.length`), you can set `x` to any of the following:
* `x + nums[i]`
* `x - nums[i]`
* `x ^ nums[i]` (bitwise-XOR)
Note that you can use each `nums[i]` any number of times in any order. Operations that set `x` to be out of the range `0 <= x <= 1000` are valid, but no more operations can be done afterward.
Return _the **minimum** number of operations needed to convert_ `x = start` _into_ `goal`_, and_ `-1` _if it is not possible_.
**Example 1:**
**Input:** nums = [2,4,12], start = 2, goal = 12
**Output:** 2
**Explanation:** We can go from 2 → 14 → 12 with the following 2 operations.
- 2 + 12 = 14
- 14 - 2 = 12
**Example 2:**
**Input:** nums = [3,5,7], start = 0, goal = -4
**Output:** 2
**Explanation:** We can go from 0 → 3 → -4 with the following 2 operations.
- 0 + 3 = 3
- 3 - 7 = -4
Note that the last operation sets x out of the range 0 <= x <= 1000, which is valid.
**Example 3:**
**Input:** nums = [2,8,16], start = 0, goal = 1
**Output:** -1
**Explanation:**
There is no way to convert 0 into 1.
**Constraints:**
* `1 <= nums.length <= 1000`
* -109 <= nums[i], goal <= 109
* `0 <= start <= 1000`
* `start != goal`
* All the integers in `nums` are distinct.