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Kotlin-based LeetCode algorithm problem solutions, regularly updated
2506\. Count Pairs Of Similar Strings
Easy
You are given a **0-indexed** string array `words`.
Two strings are **similar** if they consist of the same characters.
* For example, `"abca"` and `"cba"` are similar since both consist of characters `'a'`, `'b'`, and `'c'`.
* However, `"abacba"` and `"bcfd"` are not similar since they do not consist of the same characters.
Return _the number of pairs_ `(i, j)` _such that_ `0 <= i < j <= word.length - 1` _and the two strings_ `words[i]` _and_ `words[j]` _are similar_.
**Example 1:**
**Input:** words = ["aba","aabb","abcd","bac","aabc"]
**Output:** 2
**Explanation:** There are 2 pairs that satisfy the conditions:
- i = 0 and j = 1 : both words[0] and words[1] only consist of characters 'a' and 'b'.
- i = 3 and j = 4 : both words[3] and words[4] only consist of characters 'a', 'b', and 'c'.
**Example 2:**
**Input:** words = ["aabb","ab","ba"]
**Output:** 3
**Explanation:** There are 3 pairs that satisfy the conditions:
- i = 0 and j = 1 : both words[0] and words[1] only consist of characters 'a' and 'b'.
- i = 0 and j = 2 : both words[0] and words[2] only consist of characters 'a' and 'b'.
- i = 1 and j = 2 : both words[1] and words[2] only consist of characters 'a' and 'b'.
**Example 3:**
**Input:** words = ["nba","cba","dba"]
**Output:** 0
**Explanation:** Since there does not exist any pair that satisfies the conditions, we return 0.
**Constraints:**
* `1 <= words.length <= 100`
* `1 <= words[i].length <= 100`
* `words[i]` consist of only lowercase English letters.