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Kotlin-based LeetCode algorithm problem solutions, regularly updated
2559\. Count Vowel Strings in Ranges
Medium
You are given a **0-indexed** array of strings `words` and a 2D array of integers `queries`.
Each query queries[i] = [li, ri]
asks us to find the number of strings present in the range li
to ri
(both **inclusive**) of `words` that start and end with a vowel.
Return _an array_ `ans` _of size_ `queries.length`_, where_ `ans[i]` _is the answer to the_ `i`th _query_.
**Note** that the vowel letters are `'a'`, `'e'`, `'i'`, `'o'`, and `'u'`.
**Example 1:**
**Input:** words = ["aba","bcb","ece","aa","e"], queries = [[0,2],[1,4],[1,1]]
**Output:** [2,3,0]
**Explanation:** The strings starting and ending with a vowel are "aba", "ece", "aa" and "e".
The answer to the query [0,2] is 2 (strings "aba" and "ece").
to query [1,4] is 3 (strings "ece", "aa", "e").
to query [1,1] is 0.
We return [2,3,0].
**Example 2:**
**Input:** words = ["a","e","i"], queries = [[0,2],[0,1],[2,2]]
**Output:** [3,2,1]
**Explanation:** Every string satisfies the conditions, so we return [3,2,1].
**Constraints:**
* 1 <= words.length <= 105
* `1 <= words[i].length <= 40`
* `words[i]` consists only of lowercase English letters.
* sum(words[i].length) <= 3 * 105
* 1 <= queries.length <= 105
* 0 <= li <= ri < words.length