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Kotlin-based LeetCode algorithm problem solutions, regularly updated
2653\. Sliding Subarray Beauty
Medium
Given an integer array `nums` containing `n` integers, find the **beauty** of each subarray of size `k`.
The **beauty** of a subarray is the xth
**smallest integer** in the subarray if it is **negative**, or `0` if there are fewer than `x` negative integers.
Return _an integer array containing_ `n - k + 1` _integers, which denote the_ **beauty** _of the subarrays **in order** from the first index in the array._
* A subarray is a contiguous **non-empty** sequence of elements within an array.
**Example 1:**
**Input:** nums = [1,-1,-3,-2,3], k = 3, x = 2
**Output:** [-1,-2,-2]
**Explanation:** There are 3 subarrays with size k = 3.
The first subarray is `[1, -1, -3]` and the 2nd smallest negative integer is -1.
The second subarray is `[-1, -3, -2]` and the 2nd smallest negative integer is -2.
The third subarray is `[-3, -2, 3] `and the 2nd smallest negative integer is -2.
**Example 2:**
**Input:** nums = [-1,-2,-3,-4,-5], k = 2, x = 2
**Output:** [-1,-2,-3,-4]
**Explanation:** There are 4 subarrays with size k = 2.
For `[-1, -2]`, the 2nd smallest negative integer is -1.
For `[-2, -3]`, the 2nd smallest negative integer is -2.
For `[-3, -4]`, the 2nd smallest negative integer is -3.
For `[-4, -5]`, the 2nd smallest negative integer is -4.
**Example 3:**
**Input:** nums = [-3,1,2,-3,0,-3], k = 2, x = 1
**Output:** [-3,0,-3,-3,-3]
**Explanation:** There are 5 subarrays with size k = 2**.**
For `[-3, 1]`, the 1st smallest negative integer is -3.
For `[1, 2]`, there is no negative integer so the beauty is 0.
For `[2, -3]`, the 1st smallest negative integer is -3.
For `[-3, 0]`, the 1st smallest negative integer is -3.
For `[0, -3]`, the 1st smallest negative integer is -3.
**Constraints:**
* `n == nums.length`
* 1 <= n <= 105
* `1 <= k <= n`
* `1 <= x <= k`
* `-50 <= nums[i] <= 50`